SOLUTION-XII B COMPUTER SCIENCE-2ND MONTHLY-AUGUST 2013
KENDRIYA VIDYALAYA NO. 1 , NAUSENABAUGH, VISAKHAPATNAM
Monthly Test (August 2013) Subject : Computer Science
Class : XII Section : B Duration: 90 Min. Max Marks :50
Attempt all questions.
Q1.
Write a function in C++ to print the count of the word “the” (ignore case while
matching) as an independent word in a text file STORY.TXT. (5Marks)
For example, if the content of the file STORY.TXT is
There was a monkey in the park.
The monkey was very naughty.
The name of the park was VUDA Park.
Then the output of the program should be 4.
ANSEWER:::A COMPLETE PROGRAM:::::
#include<fstream.h>
#include<stdlib.h>
#include<stdio.h>
void main()
{
ofstream fout;
fout.open("text.txt",ios::out);
char
a[500];
cout<<"\n Enter
content of file:";
gets(a);
fout<<a;
fout.close();
ifstream fin("text.txt");
char
word[50];
int
count=0;
if(fin)
{
while(!fin.eof())
{
fin>>word;
if(strcmpi(word,
"the") == 0) //i--ignore case
while comparing
count++;
}
fin.close(); /* close the input
file */
}
cout<<”\n No of occurrences :
“<<count;
system("PAUSE"); //Press any key to continue...
}
*******************************************EXACT
ANSWER********
int
count_word_occurence(char filename[], char pattern[])
{
ifstream fin(filename);
char word[50];
int count=0;
if(fin)
{
while(!fin.eof())
{
fin>>word;
if(strcmpi(word,pattern) == 0)
count++;
}
fin.close();
}
return count;
}
Q2. Assume a text file “Test.txt”
is already created. Using this file, write a function to create three files
“LOWER.TXT” which contains all the lowercase vowels and “UPPER.TXT” which
contains all the uppercase vowels and “DIGIT.TXT” which contains all digits. ********************COMPLETE
PROGRAM*************************
#include<fstream.h>
#include<stdlib.h>
#include<stdio.h>
#include<ctype.h>
void divide_content(char filename[]);
void main()
{
divide_content("test.txt");
system("PAUSE"); //Press any key to
continue...
}
void divide_content(char filename[])
{
ifstream fin(filename);
ofstream Lfile("LOWER.TXT");
ofstream Ufile("UPPER.TXT");
ofstream Dfile("DIGIT.TXT");
char c;
if(fin)
{
while(!fin.eof())
{
fin.get(c);
if(islower(c)) Lfile.put(c);
if(isupper(c)) Ufile.put(c);
if(isdigit(c)) Dfile.put(c);
}
}
fin.close();
Lfile.close();
Ufile.close();
Dfile.close();
}
******************
EXACT ANSWER********************
void divide_content()
{
ifstream
fin("Test.txt"));
ofstream
Lfile("LOWER.TXT");
ofstream
Ufile("UPPER.TXT");
ofstream
Dfile("DIGIT.TXT");
char c;
if(fin)
{
while(!fin.eof())
{
fin.get(c);
if(islower(c)) Lfile.put(c);
if(isupper(c)) Ufile.put(c);
if(isdigit(c)) Dfile.put(c);
}
}
fin.close();
Lfile.close();
Ufile.close();
Dfile.close();
}
Q3. Write a function in a C++ to count the average
word size in a text file “BOOK.txt” (5M)
*******************A COMPLETE
PROG********************************
#include<fstream.h>
#include<stdlib.h>
#include<stdio.h>
void main()
{
ofstream
fout;
fout.open("BOOK.txt",ios::out);
char
a[500];
cout<<"\n Enter
content of file:";
gets(a);
fout<<a;
fout.close();
ifstream
fin("BOOK.txt");
char
word[50];
int
size=0,count=0;
if(fin)
{
while(!fin.eof())
{
fin>>word;
if(strlen(word))
// to avoid spaces used after the end of last word
{ // "the
the abc " has 3 words
...not 4 words
size=size+strlen(word);
count++;
}
}
fin.close(); /* close the input
file */
}
cout<<"\n No of words :
"<<count;
cout<<"\n Total size
of all words :
"<<size;
cout<<"\n Average size of word : "<< (float)size/count;
//
(float)size/count OR (float)size/(float)count OR (float)size/(float)count
system("PAUSE"); //Press any key to continue...
}
*********************Exact Answer**********************
void
averageWordSize()
{
ifstream fin("BOOK.txt");
char word[50];
int size=0,count=0;
if(fin)
{
while(!fin.eof())
{
fin>>word;
if(strlen(word)) // to avoid spaces
used after the end of last word
{ // "the
the abc " has 3 words
...not 4 words
size=size+strlen(word);
count++;
}
}
fin.close(); /* close the input file */
}
cout<<"\n No of words : "<<count;
cout<<"\n Total size of all words : "<<size;
cout<<"\n Average size of word
: "<< (float)size/count;
}
Q4. Write a function in C++ to add
new objects at the bottom of a binary file STUDENT.DAT”, assuming the binary file is containing the
objects of the following class. (5M)
class STUD {
int Rno;
char Name[20];
public: void Enter() { cin>>Rno;gets(Name);}
void
Display(){cout<<Rno<<Name<<endl;} };
*************************************EXACT
ANSWER******
Void addATend()
{ STUD s;
ofstream
f("student.dat",ios::binary|ios::ate); //u can use ios::app also
s.enter();
f.write((char*)&s,sizeof(s));
f2.close();
}
Q5. Observe the program segment
carefully and answer the question that follows: (2M)
class item {
int item_no;
char item_name[20];
public:
void enterDetail( );
void showDetail( );
int getItem_no( ){ return item_no;}
};
void modify(item x, int y ) {
fstream File;
File.open( “item.dat”, ios::binary
| ios::in | ios::out) ;
item i;
int recordsRead = 0, found = 0;
while(!found &&
File.read((char*) &i , sizeof (i))){
recordsRead++;
if(i . getItem_no( ) = = y ){
_________________________//Missing
statement
File.write((char*) &x , sizeof
(x));
found = 1;}}
if(! found)
cout<<”Record for
modification does not exist” ;
File.close() ; }
If the function modify( ) is
supposed to modify a record in the file “ item.dat “, which item_no is y, with
the values of item x passed as argument, write the appropriate statement for
the missing statement using seekp( ) or seekg( ), whichever is needed, in the
above code that would write the modified record at its proper place.
****************ANSWER****************
File.seekp(sizeof(item)*(recordsRead-1)); OR File.seekp(File.tellg( ) – sizeof(item));
Q6. Observe the program segment
carefully and answer the question that follows: (2M)
class item {int item_no;
char item_name[20];
public:
void enterDetails( );
void showDetail( );
int getItem_no( ){ return
item_no;}};
void modify(item x )
{fstream File;
File.open( “item.dat”,
_______________ ) ; //parameter missing
item i;
while(File .read((char*) & i ,
sizeof (i)))
{if(x . getItem_no( ) = = i .
getItem_no( ))
{File.seekp(File.tellg(
) – sizeof(i));
File.write((char*) &x , sizeof
(x));
} else
File.write((char*) &i , sizeof
(i));
}
File.close() ;
}
If the function modify( ) modifies a record in the file “ item.dat “
with the values
of item x passed as argument,
write the appropriate parameter for the missing
parameter in the above code, so as
to modify record at its proper place.
************************ANSWER***************
File.open( “item.dat”, ios::in| ios::out | ios::binary);
Q7. Observe the program segment carefully and
answer the question that follows: (5M)
class item {int item_no;
char item_name[20];
public:
void enterDetail( );
void showDetail( );
int getItem_no( ){ return
item_no;}};
void modify(item x ){
fstream File;
File.open( “item.dat”,
ios::binary|ios::in|ios::out ) ;
item i;
while(File .read((char*) & i ,
sizeof (i)))//Statement 1
{ if(x . getItem_no( ) = = i .
getItem_no( )){File.seekp(File.tellg( ) – sizeof(i));
File.write((char*) &x , sizeof
(x));
}} File. close () ;}
If the function modify ( )
modifies a record in the file “ item.dat” with the values of item x passed as
argument, rewrite statement 1 in the above code using eof( ), so as to modify
record at its proper place.
*****************ANSWER****************************
while(!File .eof())) {read((char*) & i , sizeof (i)));…………………………………….
Q8. Explain
the following: get pointer, put pointer,
seekg(),seekp(),tellp() ,tellg() (6
Marks)
Q9. What is
difference between Text File and Binary File ? (5 Marks)
Q10. Discuss various
File opening modes for Text and Binary Files separately. (5Marks)
Q11. Write a function that concatenates content of
one existing Text file with the content of another Text file. Don’t use any
temporary third file. (5Marks)
***************Exact answer****************************
void
concat2Files()
{
ofstream fout;
fout.open("FIRST.txt",ios::app);
ifstream fin;
fin.open("SECOND.txt");
while(!fin.eof())
{
char c;
fin.get(c);
fout.put(c);
}
fin.close();
fout.close();
}
****************************END*************************************
